Metamath Proof Explorer


Theorem lbinfle

Description: If a set of reals contains a lower bound, its infimum is less than or equal to all members of the set. (Contributed by NM, 11-Oct-2005) (Revised by AV, 4-Sep-2020)

Ref Expression
Assertion lbinfle ⊢ S ⊆ ℝ ∧ ∃ x ∈ S ∀ y ∈ S x ≤ y ∧ A ∈ S → inf S ℝ < ≤ A

Proof

Step Hyp Ref Expression
1 lbinf ⊢ S ⊆ ℝ ∧ ∃ x ∈ S ∀ y ∈ S x ≤ y → inf S ℝ < = ι x ∈ S | ∀ y ∈ S x ≤ y
2 1 3adant3 ⊢ S ⊆ ℝ ∧ ∃ x ∈ S ∀ y ∈ S x ≤ y ∧ A ∈ S → inf S ℝ < = ι x ∈ S | ∀ y ∈ S x ≤ y
3 lble ⊢ S ⊆ ℝ ∧ ∃ x ∈ S ∀ y ∈ S x ≤ y ∧ A ∈ S → ι x ∈ S | ∀ y ∈ S x ≤ y ≤ A
4 2 3 eqbrtrd ⊢ S ⊆ ℝ ∧ ∃ x ∈ S ∀ y ∈ S x ≤ y ∧ A ∈ S → inf S ℝ < ≤ A