Metamath Proof Explorer


Theorem lcfrlem10

Description: Lemma for lcfr . (Contributed by NM, 23-Feb-2015)

Ref Expression
Hypotheses lcf1o.h ⊢ H = LHyp ⁡ K
lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
lcf1o.v ⊢ V = Base U
lcf1o.a ⊢ + ˙ = + U
lcf1o.t ⊢ · ˙ = ⋅ U
lcf1o.s ⊢ S = Scalar ⁡ U
lcf1o.r ⊢ R = Base S
lcf1o.z ⊢ 0 ˙ = 0 U
lcf1o.f ⊢ F = LFnl ⁡ U
lcf1o.l ⊢ L = LKer ⁡ U
lcf1o.d ⊢ D = LDual ⁡ U
lcf1o.q ⊢ Q = 0 D
lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
Assertion lcfrlem10 ⊢ φ → J ⁡ X ∈ F

Proof

Step Hyp Ref Expression
1 lcf1o.h ⊢ H = LHyp ⁡ K
2 lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcf1o.v ⊢ V = Base U
5 lcf1o.a ⊢ + ˙ = + U
6 lcf1o.t ⊢ · ˙ = ⋅ U
7 lcf1o.s ⊢ S = Scalar ⁡ U
8 lcf1o.r ⊢ R = Base S
9 lcf1o.z ⊢ 0 ˙ = 0 U
10 lcf1o.f ⊢ F = LFnl ⁡ U
11 lcf1o.l ⊢ L = LKer ⁡ U
12 lcf1o.d ⊢ D = LDual ⁡ U
13 lcf1o.q ⊢ Q = 0 D
14 lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
15 lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
16 lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
17 lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
18 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 lcfrlem8 ⊢ φ → J ⁡ X = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X
19 eqid ⊢ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X
20 1 2 3 4 9 5 6 10 7 8 19 16 17 dochflcl ⊢ φ → v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X ∈ F
21 18 20 eqeltrd ⊢ φ → J ⁡ X ∈ F