Metamath Proof Explorer


Theorem letrd

Description: Transitive law deduction for 'less than or equal to'. (Contributed by NM, 20-May-2005)

Ref Expression
Hypotheses ltd.1 ⊢ φ → A ∈ ℝ
ltd.2 ⊢ φ → B ∈ ℝ
letrd.3 ⊢ φ → C ∈ ℝ
letrd.4 ⊢ φ → A ≤ B
letrd.5 ⊢ φ → B ≤ C
Assertion letrd ⊢ φ → A ≤ C

Proof

Step Hyp Ref Expression
1 ltd.1 ⊢ φ → A ∈ ℝ
2 ltd.2 ⊢ φ → B ∈ ℝ
3 letrd.3 ⊢ φ → C ∈ ℝ
4 letrd.4 ⊢ φ → A ≤ B
5 letrd.5 ⊢ φ → B ≤ C
6 letr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → A ≤ B ∧ B ≤ C → A ≤ C
7 1 2 3 6 syl3anc ⊢ φ → A ≤ B ∧ B ≤ C → A ≤ C
8 4 5 7 mp2and ⊢ φ → A ≤ C