Metamath Proof Explorer


Theorem letrd

Description: Transitive law deduction for 'less than or equal to'. (Contributed by NM, 20-May-2005)

Ref Expression
Hypotheses ltd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
ltd.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
letrd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
letrd.4 ⊢ ( 𝜑 → 𝐴 ≤ 𝐵 )
letrd.5 ⊢ ( 𝜑 → 𝐵 ≤ 𝐶 )
Assertion letrd ( 𝜑 → 𝐴 ≤ 𝐶 )

Proof

Step Hyp Ref Expression
1 ltd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 ltd.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 letrd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
4 letrd.4 ⊢ ( 𝜑 → 𝐴 ≤ 𝐵 )
5 letrd.5 ⊢ ( 𝜑 → 𝐵 ≤ 𝐶 )
6 letr ⊢ ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ ) → ( ( 𝐴 ≤ 𝐵 ∧ 𝐵 ≤ 𝐶 ) → 𝐴 ≤ 𝐶 ) )
7 1 2 3 6 syl3anc ⊢ ( 𝜑 → ( ( 𝐴 ≤ 𝐵 ∧ 𝐵 ≤ 𝐶 ) → 𝐴 ≤ 𝐶 ) )
8 4 5 7 mp2and ⊢ ( 𝜑 → 𝐴 ≤ 𝐶 )