Metamath Proof Explorer


Theorem lkrf0

Description: The value of a functional at a member of its kernel is zero. (Contributed by NM, 16-Apr-2014)

Ref Expression
Hypotheses lkrf0.d ⊢ D = Scalar ⁡ W
lkrf0.o ⊢ 0 ˙ = 0 D
lkrf0.f ⊢ F = LFnl ⁡ W
lkrf0.k ⊢ K = LKer ⁡ W
Assertion lkrf0 ⊢ W ∈ Y ∧ G ∈ F ∧ X ∈ K ⁡ G → G ⁡ X = 0 ˙

Proof

Step Hyp Ref Expression
1 lkrf0.d ⊢ D = Scalar ⁡ W
2 lkrf0.o ⊢ 0 ˙ = 0 D
3 lkrf0.f ⊢ F = LFnl ⁡ W
4 lkrf0.k ⊢ K = LKer ⁡ W
5 eqid ⊢ Base W = Base W
6 5 1 2 3 4 ellkr ⊢ W ∈ Y ∧ G ∈ F → X ∈ K ⁡ G ↔ X ∈ Base W ∧ G ⁡ X = 0 ˙
7 6 simplbda ⊢ W ∈ Y ∧ G ∈ F ∧ X ∈ K ⁡ G → G ⁡ X = 0 ˙
8 7 3impa ⊢ W ∈ Y ∧ G ∈ F ∧ X ∈ K ⁡ G → G ⁡ X = 0 ˙