Metamath Proof Explorer


Theorem lkrss

Description: The kernel of a scalar product of a functional includes the kernel of the functional. (Contributed by NM, 27-Jan-2015)

Ref Expression
Hypotheses lkrss.r ⊢ R = Scalar ⁡ W
lkrss.k ⊢ K = Base R
lkrss.f ⊢ F = LFnl ⁡ W
lkrss.l ⊢ L = LKer ⁡ W
lkrss.d ⊢ D = LDual ⁡ W
lkrss.s ⊢ · ˙ = ⋅ D
lkrss.w ⊢ φ → W ∈ LVec
lkrss.g ⊢ φ → G ∈ F
lkrss.x ⊢ φ → X ∈ K
Assertion lkrss ⊢ φ → L ⁡ G ⊆ L ⁡ X · ˙ G

Proof

Step Hyp Ref Expression
1 lkrss.r ⊢ R = Scalar ⁡ W
2 lkrss.k ⊢ K = Base R
3 lkrss.f ⊢ F = LFnl ⁡ W
4 lkrss.l ⊢ L = LKer ⁡ W
5 lkrss.d ⊢ D = LDual ⁡ W
6 lkrss.s ⊢ · ˙ = ⋅ D
7 lkrss.w ⊢ φ → W ∈ LVec
8 lkrss.g ⊢ φ → G ∈ F
9 lkrss.x ⊢ φ → X ∈ K
10 eqid ⊢ Base W = Base W
11 eqid ⊢ ⋅ R = ⋅ R
12 10 1 2 11 3 4 7 8 9 lkrscss ⊢ φ → L ⁡ G ⊆ L ⁡ G ⋅ R f Base W × X
13 3 10 1 2 11 5 6 7 9 8 ldualvs ⊢ φ → X · ˙ G = G ⋅ R f Base W × X
14 13 fveq2d ⊢ φ → L ⁡ X · ˙ G = L ⁡ G ⋅ R f Base W × X
15 12 14 sseqtrrd ⊢ φ → L ⁡ G ⊆ L ⁡ X · ˙ G