Metamath Proof Explorer


Theorem lsmdisj3

Description: Association of the disjointness constraint in a subgroup sum. (Contributed by Mario Carneiro, 21-Apr-2016)

Ref Expression
Hypotheses lsmcntz.p ⊢ ⊕ ˙ = LSSum ⁡ G
lsmcntz.s ⊢ φ → S ∈ SubGrp ⁡ G
lsmcntz.t ⊢ φ → T ∈ SubGrp ⁡ G
lsmcntz.u ⊢ φ → U ∈ SubGrp ⁡ G
lsmdisj.o ⊢ 0 ˙ = 0 G
lsmdisj.i ⊢ φ → S ⊕ ˙ T ∩ U = 0 ˙
lsmdisj2.i ⊢ φ → S ∩ T = 0 ˙
lsmdisj3.z ⊢ Z = Cntz ⁡ G
lsmdisj3.s ⊢ φ → S ⊆ Z ⁡ T
Assertion lsmdisj3 ⊢ φ → S ∩ T ⊕ ˙ U = 0 ˙

Proof

Step Hyp Ref Expression
1 lsmcntz.p ⊢ ⊕ ˙ = LSSum ⁡ G
2 lsmcntz.s ⊢ φ → S ∈ SubGrp ⁡ G
3 lsmcntz.t ⊢ φ → T ∈ SubGrp ⁡ G
4 lsmcntz.u ⊢ φ → U ∈ SubGrp ⁡ G
5 lsmdisj.o ⊢ 0 ˙ = 0 G
6 lsmdisj.i ⊢ φ → S ⊕ ˙ T ∩ U = 0 ˙
7 lsmdisj2.i ⊢ φ → S ∩ T = 0 ˙
8 lsmdisj3.z ⊢ Z = Cntz ⁡ G
9 lsmdisj3.s ⊢ φ → S ⊆ Z ⁡ T
10 1 8 lsmcom2 ⊢ S ∈ SubGrp ⁡ G ∧ T ∈ SubGrp ⁡ G ∧ S ⊆ Z ⁡ T → S ⊕ ˙ T = T ⊕ ˙ S
11 2 3 9 10 syl3anc ⊢ φ → S ⊕ ˙ T = T ⊕ ˙ S
12 11 ineq1d ⊢ φ → S ⊕ ˙ T ∩ U = T ⊕ ˙ S ∩ U
13 12 6 eqtr3d ⊢ φ → T ⊕ ˙ S ∩ U = 0 ˙
14 incom ⊢ T ∩ S = S ∩ T
15 14 7 eqtrid ⊢ φ → T ∩ S = 0 ˙
16 1 3 2 4 5 13 15 lsmdisj2 ⊢ φ → S ∩ T ⊕ ˙ U = 0 ˙