Metamath Proof Explorer


Theorem lspprvacl

Description: The sum of two vectors belongs to their span. (Contributed by NM, 20-May-2015)

Ref Expression
Hypotheses lspprvacl.v ⊢ V = Base W
lspprvacl.p ⊢ + ˙ = + W
lspprvacl.n ⊢ N = LSpan ⁡ W
lspprvacl.w ⊢ φ → W ∈ LMod
lspprvacl.x ⊢ φ → X ∈ V
lspprvacl.y ⊢ φ → Y ∈ V
Assertion lspprvacl ⊢ φ → X + ˙ Y ∈ N ⁡ X Y

Proof

Step Hyp Ref Expression
1 lspprvacl.v ⊢ V = Base W
2 lspprvacl.p ⊢ + ˙ = + W
3 lspprvacl.n ⊢ N = LSpan ⁡ W
4 lspprvacl.w ⊢ φ → W ∈ LMod
5 lspprvacl.x ⊢ φ → X ∈ V
6 lspprvacl.y ⊢ φ → Y ∈ V
7 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
8 1 7 3 4 5 6 lspprcl ⊢ φ → N ⁡ X Y ∈ LSubSp ⁡ W
9 1 3 4 5 6 lspprid1 ⊢ φ → X ∈ N ⁡ X Y
10 1 3 4 5 6 lspprid2 ⊢ φ → Y ∈ N ⁡ X Y
11 2 7 lssvacl ⊢ W ∈ LMod ∧ N ⁡ X Y ∈ LSubSp ⁡ W ∧ X ∈ N ⁡ X Y ∧ Y ∈ N ⁡ X Y → X + ˙ Y ∈ N ⁡ X Y
12 4 8 9 10 11 syl22anc ⊢ φ → X + ˙ Y ∈ N ⁡ X Y