Metamath Proof Explorer
Description: A subspace member is a vector. (Contributed by NM, 11-Jan-2014)
(Revised by Mario Carneiro, 8-Jan-2015)
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|
Ref |
Expression |
|
Hypotheses |
lssss.v |
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|
lssss.s |
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Assertion |
lssel |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
lssss.v |
|
| 2 |
|
lssss.s |
|
| 3 |
1 2
|
lssss |
|
| 4 |
3
|
sselda |
|