Metamath Proof Explorer


Theorem lttri2

Description: Consequence of trichotomy. (Contributed by NM, 9-Oct-1999)

Ref Expression
Assertion lttri2 ⊢ A ∈ ℝ ∧ B ∈ ℝ → A ≠ B ↔ A < B ∨ B < A

Proof

Step Hyp Ref Expression
1 ltso ⊢ < Or ℝ
2 sotrieq ⊢ < Or ℝ ∧ A ∈ ℝ ∧ B ∈ ℝ → A = B ↔ ¬ A < B ∨ B < A
3 1 2 mpan ⊢ A ∈ ℝ ∧ B ∈ ℝ → A = B ↔ ¬ A < B ∨ B < A
4 3 bicomd ⊢ A ∈ ℝ ∧ B ∈ ℝ → ¬ A < B ∨ B < A ↔ A = B
5 4 necon1abid ⊢ A ∈ ℝ ∧ B ∈ ℝ → A ≠ B ↔ A < B ∨ B < A