Metamath Proof Explorer


Theorem mbfeqa

Description: If two functions are equal almost everywhere, then one is measurable iff the other is. (Contributed by Mario Carneiro, 17-Jun-2014) (Revised by Mario Carneiro, 2-Sep-2014)

Ref Expression
Hypotheses mbfeqa.1 ⊢ φ → A ⊆ ℝ
mbfeqa.2 ⊢ φ → vol * ⁡ A = 0
mbfeqa.3 ⊢ φ ∧ x ∈ B ∖ A → C = D
mbfeqa.4 ⊢ φ ∧ x ∈ B → C ∈ ℂ
mbfeqa.5 ⊢ φ ∧ x ∈ B → D ∈ ℂ
Assertion mbfeqa ⊢ φ → x ∈ B ⟼ C ∈ MblFn ↔ x ∈ B ⟼ D ∈ MblFn

Proof

Step Hyp Ref Expression
1 mbfeqa.1 ⊢ φ → A ⊆ ℝ
2 mbfeqa.2 ⊢ φ → vol * ⁡ A = 0
3 mbfeqa.3 ⊢ φ ∧ x ∈ B ∖ A → C = D
4 mbfeqa.4 ⊢ φ ∧ x ∈ B → C ∈ ℂ
5 mbfeqa.5 ⊢ φ ∧ x ∈ B → D ∈ ℂ
6 3 fveq2d ⊢ φ ∧ x ∈ B ∖ A → ℜ ⁡ C = ℜ ⁡ D
7 4 recld ⊢ φ ∧ x ∈ B → ℜ ⁡ C ∈ ℝ
8 5 recld ⊢ φ ∧ x ∈ B → ℜ ⁡ D ∈ ℝ
9 1 2 6 7 8 mbfeqalem2 ⊢ φ → x ∈ B ⟼ ℜ ⁡ C ∈ MblFn ↔ x ∈ B ⟼ ℜ ⁡ D ∈ MblFn
10 3 fveq2d ⊢ φ ∧ x ∈ B ∖ A → ℑ ⁡ C = ℑ ⁡ D
11 4 imcld ⊢ φ ∧ x ∈ B → ℑ ⁡ C ∈ ℝ
12 5 imcld ⊢ φ ∧ x ∈ B → ℑ ⁡ D ∈ ℝ
13 1 2 10 11 12 mbfeqalem2 ⊢ φ → x ∈ B ⟼ ℑ ⁡ C ∈ MblFn ↔ x ∈ B ⟼ ℑ ⁡ D ∈ MblFn
14 9 13 anbi12d ⊢ φ → x ∈ B ⟼ ℜ ⁡ C ∈ MblFn ∧ x ∈ B ⟼ ℑ ⁡ C ∈ MblFn ↔ x ∈ B ⟼ ℜ ⁡ D ∈ MblFn ∧ x ∈ B ⟼ ℑ ⁡ D ∈ MblFn
15 4 ismbfcn2 ⊢ φ → x ∈ B ⟼ C ∈ MblFn ↔ x ∈ B ⟼ ℜ ⁡ C ∈ MblFn ∧ x ∈ B ⟼ ℑ ⁡ C ∈ MblFn
16 5 ismbfcn2 ⊢ φ → x ∈ B ⟼ D ∈ MblFn ↔ x ∈ B ⟼ ℜ ⁡ D ∈ MblFn ∧ x ∈ B ⟼ ℑ ⁡ D ∈ MblFn
17 14 15 16 3bitr4d ⊢ φ → x ∈ B ⟼ C ∈ MblFn ↔ x ∈ B ⟼ D ∈ MblFn