Metamath Proof Explorer


Theorem mnringvscad

Description: The scalar product of a monoid ring. (Contributed by Rohan Ridenour, 14-May-2024) (Proof shortened by AV, 1-Nov-2024)

Ref Expression
Hypotheses mnringvscad.1 ⊢ F = R MndRing M
mnringvscad.2 ⊢ B = Base M
mnringvscad.3 ⊢ V = R freeLMod B
mnringvscad.4 ⊢ φ → R ∈ U
mnringvscad.5 ⊢ φ → M ∈ W
Assertion mnringvscad ⊢ φ → ⋅ V = ⋅ F

Proof

Step Hyp Ref Expression
1 mnringvscad.1 ⊢ F = R MndRing M
2 mnringvscad.2 ⊢ B = Base M
3 mnringvscad.3 ⊢ V = R freeLMod B
4 mnringvscad.4 ⊢ φ → R ∈ U
5 mnringvscad.5 ⊢ φ → M ∈ W
6 vscaid ⊢ ⋅ 𝑠 = Slot ⋅ ndx
7 vscandxnmulrndx ⊢ ⋅ ndx ≠ ⋅ ndx
8 1 6 7 2 3 4 5 mnringnmulrd ⊢ φ → ⋅ V = ⋅ F