Metamath Proof Explorer


Theorem mpsyl4anc

Description: An elimination deduction. (Contributed by Alan Sare, 17-Oct-2017)

Ref Expression
Hypotheses mpsyl4anc.1 ⊢ φ
mpsyl4anc.2 ⊢ ψ
mpsyl4anc.3 ⊢ χ
mpsyl4anc.4 ⊢ θ → τ
mpsyl4anc.5 ⊢ φ ∧ ψ ∧ χ ∧ τ → η
Assertion mpsyl4anc ⊢ θ → η

Proof

Step Hyp Ref Expression
1 mpsyl4anc.1 ⊢ φ
2 mpsyl4anc.2 ⊢ ψ
3 mpsyl4anc.3 ⊢ χ
4 mpsyl4anc.4 ⊢ θ → τ
5 mpsyl4anc.5 ⊢ φ ∧ ψ ∧ χ ∧ τ → η
6 1 a1i ⊢ θ → φ
7 2 a1i ⊢ θ → ψ
8 3 a1i ⊢ θ → χ
9 6 7 8 4 5 syl1111anc ⊢ θ → η