Metamath Proof Explorer


Theorem mxidln1

Description: One is not contained in any maximal ideal. (Contributed by Jeff Madsen, 17-Jun-2011) (Revised by Thierry Arnoux, 19-Jan-2024)

Ref Expression
Hypotheses mxidlval.1 ⊢ B = Base R
mxidln1.1 ⊢ 1 ˙ = 1 R
Assertion mxidln1 ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → ¬ 1 ˙ ∈ M

Proof

Step Hyp Ref Expression
1 mxidlval.1 ⊢ B = Base R
2 mxidln1.1 ⊢ 1 ˙ = 1 R
3 1 mxidlnr ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → M ≠ B
4 1 mxidlidl ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → M ∈ LIdeal ⁡ R
5 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
6 5 1 2 lidl1el ⊢ R ∈ Ring ∧ M ∈ LIdeal ⁡ R → 1 ˙ ∈ M ↔ M = B
7 4 6 syldan ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → 1 ˙ ∈ M ↔ M = B
8 7 necon3bbid ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → ¬ 1 ˙ ∈ M ↔ M ≠ B
9 3 8 mpbird ⊢ R ∈ Ring ∧ M ∈ MaxIdeal ⁡ R → ¬ 1 ˙ ∈ M