Metamath Proof Explorer


Theorem nmlnop0iHIL

Description: A linear operator with a zero norm is identically zero. (Contributed by NM, 18-Jan-2008) (New usage is discouraged.)

Ref Expression
Hypothesis nmlnop0.1 ⊢ T ∈ LinOp
Assertion nmlnop0iHIL ⊢ norm op ⁡ T = 0 ↔ T = 0 hop

Proof

Step Hyp Ref Expression
1 nmlnop0.1 ⊢ T ∈ LinOp
2 eqid ⊢ + ℎ ⋅ ℎ norm ℎ = + ℎ ⋅ ℎ norm ℎ
3 eqid ⊢ + ℎ ⋅ ℎ norm ℎ normOp OLD + ℎ ⋅ ℎ norm ℎ = + ℎ ⋅ ℎ norm ℎ normOp OLD + ℎ ⋅ ℎ norm ℎ
4 2 3 hhnmoi ⊢ norm op = + ℎ ⋅ ℎ norm ℎ normOp OLD + ℎ ⋅ ℎ norm ℎ
5 eqid ⊢ + ℎ ⋅ ℎ norm ℎ 0 op + ℎ ⋅ ℎ norm ℎ = + ℎ ⋅ ℎ norm ℎ 0 op + ℎ ⋅ ℎ norm ℎ
6 2 5 hh0oi ⊢ 0 hop = + ℎ ⋅ ℎ norm ℎ 0 op + ℎ ⋅ ℎ norm ℎ
7 eqid ⊢ + ℎ ⋅ ℎ norm ℎ LnOp + ℎ ⋅ ℎ norm ℎ = + ℎ ⋅ ℎ norm ℎ LnOp + ℎ ⋅ ℎ norm ℎ
8 2 7 hhlnoi ⊢ LinOp = + ℎ ⋅ ℎ norm ℎ LnOp + ℎ ⋅ ℎ norm ℎ
9 2 hhnv ⊢ + ℎ ⋅ ℎ norm ℎ ∈ NrmCVec
10 4 6 8 9 9 nmlno0i ⊢ T ∈ LinOp → norm op ⁡ T = 0 ↔ T = 0 hop
11 1 10 ax-mp ⊢ norm op ⁡ T = 0 ↔ T = 0 hop