Metamath Proof Explorer


Theorem nna1iscard

Description: For any natural number, the add one operation is results in a cardinal number. (Contributed by RP, 1-Oct-2023)

Ref Expression
Assertion nna1iscard N ω N + 𝑜 1 𝑜 ran card

Proof

Step Hyp Ref Expression
1 nnon N ω N On
2 oa1suc N On N + 𝑜 1 𝑜 = suc N
3 1 2 syl N ω N + 𝑜 1 𝑜 = suc N
4 peano2 N ω suc N ω
5 3 4 jca N ω N + 𝑜 1 𝑜 = suc N suc N ω
6 simpl N + 𝑜 1 𝑜 = suc N suc N ω N + 𝑜 1 𝑜 = suc N
7 simpr N + 𝑜 1 𝑜 = suc N suc N ω suc N ω
8 6 7 eqeltrd N + 𝑜 1 𝑜 = suc N suc N ω N + 𝑜 1 𝑜 ω
9 omssrncard ω ran card
10 9 sseli N + 𝑜 1 𝑜 ω N + 𝑜 1 𝑜 ran card
11 5 8 10 3syl N ω N + 𝑜 1 𝑜 ran card