Metamath Proof Explorer


Theorem nnadd1com

Description: Addition with 1 is commutative for natural numbers. (Contributed by Steven Nguyen, 9-Dec-2022)

Ref Expression
Assertion nnadd1com ⊢ A ∈ ℕ → A + 1 = 1 + A

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ x = 1 → x + 1 = 1 + 1
2 oveq2 ⊢ x = 1 → 1 + x = 1 + 1
3 1 2 eqeq12d ⊢ x = 1 → x + 1 = 1 + x ↔ 1 + 1 = 1 + 1
4 oveq1 ⊢ x = y → x + 1 = y + 1
5 oveq2 ⊢ x = y → 1 + x = 1 + y
6 4 5 eqeq12d ⊢ x = y → x + 1 = 1 + x ↔ y + 1 = 1 + y
7 oveq1 ⊢ x = y + 1 → x + 1 = y + 1 + 1
8 oveq2 ⊢ x = y + 1 → 1 + x = 1 + y + 1
9 7 8 eqeq12d ⊢ x = y + 1 → x + 1 = 1 + x ↔ y + 1 + 1 = 1 + y + 1
10 oveq1 ⊢ x = A → x + 1 = A + 1
11 oveq2 ⊢ x = A → 1 + x = 1 + A
12 10 11 eqeq12d ⊢ x = A → x + 1 = 1 + x ↔ A + 1 = 1 + A
13 eqid ⊢ 1 + 1 = 1 + 1
14 oveq1 ⊢ y + 1 = 1 + y → y + 1 + 1 = 1 + y + 1
15 1cnd ⊢ y ∈ ℕ → 1 ∈ ℂ
16 nncn ⊢ y ∈ ℕ → y ∈ ℂ
17 15 16 15 addassd ⊢ y ∈ ℕ → 1 + y + 1 = 1 + y + 1
18 14 17 sylan9eqr ⊢ y ∈ ℕ ∧ y + 1 = 1 + y → y + 1 + 1 = 1 + y + 1
19 18 ex ⊢ y ∈ ℕ → y + 1 = 1 + y → y + 1 + 1 = 1 + y + 1
20 3 6 9 12 13 19 nnind ⊢ A ∈ ℕ → A + 1 = 1 + A