Metamath Proof Explorer


Theorem oa0r

Description: Ordinal addition with zero. Proposition 8.3 of TakeutiZaring p. 57. Lemma 2.14 of Schloeder p. 5. (Contributed by NM, 5-May-1995)

Ref Expression
Assertion oa0r ⊢ A ∈ On → ∅ + 𝑜 A = A

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ x = ∅ → ∅ + 𝑜 x = ∅ + 𝑜 ∅
2 id ⊢ x = ∅ → x = ∅
3 1 2 eqeq12d ⊢ x = ∅ → ∅ + 𝑜 x = x ↔ ∅ + 𝑜 ∅ = ∅
4 oveq2 ⊢ x = y → ∅ + 𝑜 x = ∅ + 𝑜 y
5 id ⊢ x = y → x = y
6 4 5 eqeq12d ⊢ x = y → ∅ + 𝑜 x = x ↔ ∅ + 𝑜 y = y
7 oveq2 ⊢ x = suc ⁡ y → ∅ + 𝑜 x = ∅ + 𝑜 suc ⁡ y
8 id ⊢ x = suc ⁡ y → x = suc ⁡ y
9 7 8 eqeq12d ⊢ x = suc ⁡ y → ∅ + 𝑜 x = x ↔ ∅ + 𝑜 suc ⁡ y = suc ⁡ y
10 oveq2 ⊢ x = A → ∅ + 𝑜 x = ∅ + 𝑜 A
11 id ⊢ x = A → x = A
12 10 11 eqeq12d ⊢ x = A → ∅ + 𝑜 x = x ↔ ∅ + 𝑜 A = A
13 0elon ⊢ ∅ ∈ On
14 oa0 ⊢ ∅ ∈ On → ∅ + 𝑜 ∅ = ∅
15 13 14 ax-mp ⊢ ∅ + 𝑜 ∅ = ∅
16 oasuc ⊢ ∅ ∈ On ∧ y ∈ On → ∅ + 𝑜 suc ⁡ y = suc ⁡ ∅ + 𝑜 y
17 13 16 mpan ⊢ y ∈ On → ∅ + 𝑜 suc ⁡ y = suc ⁡ ∅ + 𝑜 y
18 suceq ⊢ ∅ + 𝑜 y = y → suc ⁡ ∅ + 𝑜 y = suc ⁡ y
19 17 18 sylan9eq ⊢ y ∈ On ∧ ∅ + 𝑜 y = y → ∅ + 𝑜 suc ⁡ y = suc ⁡ y
20 19 ex ⊢ y ∈ On → ∅ + 𝑜 y = y → ∅ + 𝑜 suc ⁡ y = suc ⁡ y
21 iuneq2 ⊢ ∀ y ∈ x ∅ + 𝑜 y = y → ⋃ y ∈ x ∅ + 𝑜 y = ⋃ y ∈ x y
22 uniiun ⊢ ⋃ x = ⋃ y ∈ x y
23 21 22 eqtr4di ⊢ ∀ y ∈ x ∅ + 𝑜 y = y → ⋃ y ∈ x ∅ + 𝑜 y = ⋃ x
24 vex ⊢ x ∈ V
25 oalim ⊢ ∅ ∈ On ∧ x ∈ V ∧ Lim ⁡ x → ∅ + 𝑜 x = ⋃ y ∈ x ∅ + 𝑜 y
26 13 25 mpan ⊢ x ∈ V ∧ Lim ⁡ x → ∅ + 𝑜 x = ⋃ y ∈ x ∅ + 𝑜 y
27 24 26 mpan ⊢ Lim ⁡ x → ∅ + 𝑜 x = ⋃ y ∈ x ∅ + 𝑜 y
28 limuni ⊢ Lim ⁡ x → x = ⋃ x
29 27 28 eqeq12d ⊢ Lim ⁡ x → ∅ + 𝑜 x = x ↔ ⋃ y ∈ x ∅ + 𝑜 y = ⋃ x
30 23 29 imbitrrid ⊢ Lim ⁡ x → ∀ y ∈ x ∅ + 𝑜 y = y → ∅ + 𝑜 x = x
31 3 6 9 12 15 20 30 tfinds ⊢ A ∈ On → ∅ + 𝑜 A = A