Metamath Proof Explorer


Theorem onnobdayg

Description: Every ordinal maps to a surreal number of that birthday. (Contributed by RP, 21-Sep-2023)

Ref Expression
Assertion onnobdayg ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → bday ⁡ A × B = A

Proof

Step Hyp Ref Expression
1 onnoxpg ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → A × B ∈ No
2 bdayval ⊢ A × B ∈ No → bday ⁡ A × B = dom ⁡ A × B
3 1 2 syl ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → bday ⁡ A × B = dom ⁡ A × B
4 simpr ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → B ∈ 1 𝑜 2 𝑜
5 snnzg ⊢ B ∈ 1 𝑜 2 𝑜 → B ≠ ∅
6 dmxp ⊢ B ≠ ∅ → dom ⁡ A × B = A
7 4 5 6 3syl ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → dom ⁡ A × B = A
8 3 7 eqtrd ⊢ A ∈ On ∧ B ∈ 1 𝑜 2 𝑜 → bday ⁡ A × B = A