Metamath Proof Explorer


Theorem onnobdayg

Description: Every ordinal maps to a surreal number of that birthday. (Contributed by RP, 21-Sep-2023)

Ref Expression
Assertion onnobdayg A On B 1 𝑜 2 𝑜 bday A × B = A

Proof

Step Hyp Ref Expression
1 onnog A On B 1 𝑜 2 𝑜 A × B No
2 bdayval A × B No bday A × B = dom A × B
3 1 2 syl A On B 1 𝑜 2 𝑜 bday A × B = dom A × B
4 simpr A On B 1 𝑜 2 𝑜 B 1 𝑜 2 𝑜
5 snnzg B 1 𝑜 2 𝑜 B
6 dmxp B dom A × B = A
7 4 5 6 3syl A On B 1 𝑜 2 𝑜 dom A × B = A
8 3 7 eqtrd A On B 1 𝑜 2 𝑜 bday A × B = A