Metamath Proof Explorer


Theorem op1stg

Description: Extract the first member of an ordered pair. (Contributed by NM, 19-Jul-2005)

Ref Expression
Assertion op1stg ⊢ A ∈ V ∧ B ∈ W → 1 st ⁡ A B = A

Proof

Step Hyp Ref Expression
1 opeq1 ⊢ x = A → x y = A y
2 1 fveq2d ⊢ x = A → 1 st ⁡ x y = 1 st ⁡ A y
3 id ⊢ x = A → x = A
4 2 3 eqeq12d ⊢ x = A → 1 st ⁡ x y = x ↔ 1 st ⁡ A y = A
5 opeq2 ⊢ y = B → A y = A B
6 5 fveqeq2d ⊢ y = B → 1 st ⁡ A y = A ↔ 1 st ⁡ A B = A
7 vex ⊢ x ∈ V
8 vex ⊢ y ∈ V
9 7 8 op1st ⊢ 1 st ⁡ x y = x
10 4 6 9 vtocl2g ⊢ A ∈ V ∧ B ∈ W → 1 st ⁡ A B = A