Metamath Proof Explorer


Theorem ply1subrg

Description: Univariate polynomials form a subring of the set of univariate power series. (Contributed by Mario Carneiro, 9-Feb-2015)

Ref Expression
Hypotheses ply1val.1 ⊢ P = Poly 1 ⁡ R
ply1lss.2 ⊢ S = PwSer 1 ⁡ R
ply1lss.u ⊢ U = Base P
Assertion ply1subrg ⊢ R ∈ Ring → U ∈ SubRing ⁡ S

Proof

Step Hyp Ref Expression
1 ply1val.1 ⊢ P = Poly 1 ⁡ R
2 ply1lss.2 ⊢ S = PwSer 1 ⁡ R
3 ply1lss.u ⊢ U = Base P
4 eqid ⊢ 1 𝑜 mPwSer R = 1 𝑜 mPwSer R
5 eqid ⊢ 1 𝑜 mPoly R = 1 𝑜 mPoly R
6 1 3 ply1bas ⊢ U = Base 1 𝑜 mPoly R
7 1on ⊢ 1 𝑜 ∈ On
8 7 a1i ⊢ R ∈ Ring → 1 𝑜 ∈ On
9 id ⊢ R ∈ Ring → R ∈ Ring
10 4 5 6 8 9 mplsubrg ⊢ R ∈ Ring → U ∈ SubRing ⁡ 1 𝑜 mPwSer R
11 eqidd ⊢ R ∈ Ring → Base 1 𝑜 mPwSer R = Base 1 𝑜 mPwSer R
12 2 psr1val ⊢ S = 1 𝑜 ordPwSer R ⁡ ∅
13 0ss ⊢ ∅ ⊆ 1 𝑜 × 1 𝑜
14 13 a1i ⊢ R ∈ Ring → ∅ ⊆ 1 𝑜 × 1 𝑜
15 4 12 14 opsrbas ⊢ R ∈ Ring → Base 1 𝑜 mPwSer R = Base S
16 4 12 14 opsrplusg ⊢ R ∈ Ring → + 1 𝑜 mPwSer R = + S
17 16 oveqdr ⊢ R ∈ Ring ∧ x ∈ Base 1 𝑜 mPwSer R ∧ y ∈ Base 1 𝑜 mPwSer R → x + 1 𝑜 mPwSer R y = x + S y
18 4 12 14 opsrmulr ⊢ R ∈ Ring → ⋅ 1 𝑜 mPwSer R = ⋅ S
19 18 oveqdr ⊢ R ∈ Ring ∧ x ∈ Base 1 𝑜 mPwSer R ∧ y ∈ Base 1 𝑜 mPwSer R → x ⋅ 1 𝑜 mPwSer R y = x ⋅ S y
20 11 15 17 19 subrgpropd ⊢ R ∈ Ring → SubRing ⁡ 1 𝑜 mPwSer R = SubRing ⁡ S
21 10 20 eleqtrd ⊢ R ∈ Ring → U ∈ SubRing ⁡ S