Metamath Proof Explorer


Theorem prlngpln3

Description: Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses prlngpln3.l ⊢ L = Line 𝒢 ⁡ G
prlngpln3.e No typesetting found for |- E = ( PlnG ` G ) with typecode |-
prlngpln3.p No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
prlngpln3.g ⊢ φ → G ∈ 𝒢 Tarski
prlngpln3.1 ⊢ φ → A ∥ ˙ B
prlngpln3.2 ⊢ φ → A ≠ B
prlngpln3.x ⊢ φ → X ∈ B
Assertion prlngpln3 ⊢ φ → B ⊆ A E X

Proof

Step Hyp Ref Expression
1 prlngpln3.l ⊢ L = Line 𝒢 ⁡ G
2 prlngpln3.e Could not format E = ( PlnG ` G ) : No typesetting found for |- E = ( PlnG ` G ) with typecode |-
3 prlngpln3.p Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
4 prlngpln3.g ⊢ φ → G ∈ 𝒢 Tarski
5 prlngpln3.1 ⊢ φ → A ∥ ˙ B
6 prlngpln3.2 ⊢ φ → A ≠ B
7 prlngpln3.x ⊢ φ → X ∈ B
8 eqid ⊢ Base G = Base G
9 1 3 4 5 prlngrcl1 ⊢ φ → A ∈ ran ⁡ L
10 9 adantr ⊢ φ ∧ y ∈ B → A ∈ ran ⁡ L
11 eqid ⊢ Itv ⁡ G = Itv ⁡ G
12 4 adantr ⊢ φ ∧ y ∈ B → G ∈ 𝒢 Tarski
13 5 adantr ⊢ φ ∧ y ∈ B → A ∥ ˙ B
14 1 3 12 13 prlngrcl2 ⊢ φ ∧ y ∈ B → B ∈ ran ⁡ L
15 simpr ⊢ φ ∧ y ∈ B → y ∈ B
16 8 1 11 12 14 15 tglnpt ⊢ φ ∧ y ∈ B → y ∈ Base G
17 1 3 4 5 prlngrcl2 ⊢ φ → B ∈ ran ⁡ L
18 8 1 11 4 17 7 tglnpt ⊢ φ → X ∈ Base G
19 incom ⊢ A ∩ B = B ∩ A
20 1 3 4 5 6 prlngin0 ⊢ φ → A ∩ B = ∅
21 19 20 eqtr3id ⊢ φ → B ∩ A = ∅
22 disjel ⊢ B ∩ A = ∅ ∧ X ∈ B → ¬ X ∈ A
23 21 7 22 syl2anc ⊢ φ → ¬ X ∈ A
24 18 23 eldifd ⊢ φ → X ∈ Base G ∖ A
25 24 adantr ⊢ φ ∧ y ∈ B → X ∈ Base G ∖ A
26 6 adantr ⊢ φ ∧ y ∈ B → A ≠ B
27 7 adantr ⊢ φ ∧ y ∈ B → X ∈ B
28 1 2 3 12 13 26 15 27 prlnghpg ⊢ φ ∧ y ∈ B → y hp 𝒢 ⁡ G ⁡ A X
29 8 1 2 10 16 25 12 28 hpgssplng ⊢ φ ∧ y ∈ B → y ∈ A E X
30 29 ex ⊢ φ → y ∈ B → y ∈ A E X
31 30 ssrdv ⊢ φ → B ⊆ A E X