Metamath Proof Explorer
Description: Practice problem 3. Clues: eqcomi eqtri subaddrii recni 4re 3re 1re df-4 addcomi . (Contributed by Filip Cernatescu, 16-Mar-2019) (Proof modification is discouraged.)
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Ref |
Expression |
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Hypotheses |
problem3.1 |
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problem3.2 |
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Assertion |
problem3 |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
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problem3.1 |
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| 2 |
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problem3.2 |
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| 3 |
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4re |
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| 4 |
3
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recni |
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| 5 |
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3re |
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| 6 |
5
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recni |
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| 7 |
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1re |
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| 8 |
7
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recni |
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| 9 |
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df-4 |
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| 10 |
9
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eqcomi |
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| 11 |
4 6 8 10
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subaddrii |
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| 12 |
11
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eqcomi |
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| 13 |
6 1
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addcomi |
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| 14 |
13 2
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eqtri |
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| 15 |
4 6 1 14
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subaddrii |
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| 16 |
12 15
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eqtri |
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| 17 |
16
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eqcomi |
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