Metamath Proof Explorer


Theorem pthsfval

Description: The set of paths (in an undirected graph). (Contributed by Alexander van der Vekens, 20-Oct-2017) (Revised by AV, 9-Jan-2021) (Revised by AV, 29-Oct-2021)

Ref Expression
Assertion pthsfval ⊢ Paths ⁡ G = f p | f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅

Proof

Step Hyp Ref Expression
1 biidd ⊢ g = G → Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ ↔ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
2 df-pths ⊢ Paths = g ∈ V ⟼ f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
3 3anass ⊢ f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ ↔ f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
4 3 opabbii ⊢ f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ = f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
5 4 mpteq2i ⊢ g ∈ V ⟼ f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ = g ∈ V ⟼ f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
6 2 5 eqtri ⊢ Paths = g ∈ V ⟼ f p | f Trails ⁡ g p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
7 1 6 fvmptopab ⊢ Paths ⁡ G = f p | f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
8 3anass ⊢ f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ ↔ f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
9 8 opabbii ⊢ f p | f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅ = f p | f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅
10 7 9 eqtr4i ⊢ Paths ⁡ G = f p | f Trails ⁡ G p ∧ Fun ⁡ p ↾ 1 ..^ f -1 ∧ p 0 f ∩ p 1 ..^ f = ∅