Metamath Proof Explorer


Theorem quotdgr

Description: Remainder property of the quotient function. (Contributed by Mario Carneiro, 26-Jul-2014)

Ref Expression
Hypothesis quotdgr.1 ⊢ R = F − f G × f F quot G
Assertion quotdgr ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G

Proof

Step Hyp Ref Expression
1 quotdgr.1 ⊢ R = F − f G × f F quot G
2 addcl ⊢ x ∈ ℂ ∧ y ∈ ℂ → x + y ∈ ℂ
3 2 adantl ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 ∧ x ∈ ℂ ∧ y ∈ ℂ → x + y ∈ ℂ
4 mulcl ⊢ x ∈ ℂ ∧ y ∈ ℂ → x ⁢ y ∈ ℂ
5 4 adantl ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 ∧ x ∈ ℂ ∧ y ∈ ℂ → x ⁢ y ∈ ℂ
6 reccl ⊢ x ∈ ℂ ∧ x ≠ 0 → 1 x ∈ ℂ
7 6 adantl ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 ∧ x ∈ ℂ ∧ x ≠ 0 → 1 x ∈ ℂ
8 neg1cn ⊢ − 1 ∈ ℂ
9 8 a1i ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → − 1 ∈ ℂ
10 plyssc ⊢ Poly ⁡ S ⊆ Poly ⁡ ℂ
11 simp1 ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → F ∈ Poly ⁡ S
12 10 11 sselid ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → F ∈ Poly ⁡ ℂ
13 simp2 ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → G ∈ Poly ⁡ S
14 10 13 sselid ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → G ∈ Poly ⁡ ℂ
15 simp3 ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → G ≠ 0 𝑝
16 3 5 7 9 12 14 15 1 quotlem ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → F quot G ∈ Poly ⁡ ℂ ∧ R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G
17 16 simprd ⊢ F ∈ Poly ⁡ S ∧ G ∈ Poly ⁡ S ∧ G ≠ 0 𝑝 → R = 0 𝑝 ∨ deg ⁡ R < deg ⁡ G