Metamath Proof Explorer


Theorem reixi

Description: ixi without ax-mulcom . (Contributed by SN, 5-May-2024)

Ref Expression
Assertion reixi ⊢ i ⁢ i = 0 - ℝ 1

Proof

Step Hyp Ref Expression
1 ax-i2m1 ⊢ i ⁢ i + 1 = 0
2 1re ⊢ 1 ∈ ℝ
3 renegid2 ⊢ 1 ∈ ℝ → 0 - ℝ 1 + 1 = 0
4 2 3 ax-mp ⊢ 0 - ℝ 1 + 1 = 0
5 1 4 eqtr4i ⊢ i ⁢ i + 1 = 0 - ℝ 1 + 1
6 ax-icn ⊢ i ∈ ℂ
7 6 6 mulcli ⊢ i ⁢ i ∈ ℂ
8 7 a1i ⊢ ⊤ → i ⁢ i ∈ ℂ
9 rernegcl ⊢ 1 ∈ ℝ → 0 - ℝ 1 ∈ ℝ
10 9 recnd ⊢ 1 ∈ ℝ → 0 - ℝ 1 ∈ ℂ
11 2 10 mp1i ⊢ ⊤ → 0 - ℝ 1 ∈ ℂ
12 1cnd ⊢ ⊤ → 1 ∈ ℂ
13 8 11 12 sn-addcan2d ⊢ ⊤ → i ⁢ i + 1 = 0 - ℝ 1 + 1 ↔ i ⁢ i = 0 - ℝ 1
14 5 13 mpbii ⊢ ⊤ → i ⁢ i = 0 - ℝ 1
15 14 mptru ⊢ i ⁢ i = 0 - ℝ 1