Metamath Proof Explorer


Theorem releldmqs

Description: Elementhood in the domain quotient of a relation. (Contributed by Peter Mazsa, 24-Apr-2021)

Ref Expression
Assertion releldmqs ⊢ A ∈ V → Rel ⁡ R → A ∈ dom ⁡ R / R ↔ ∃ u ∈ dom ⁡ R ∃ x ∈ u R A = u R

Proof

Step Hyp Ref Expression
1 resdm ⊢ Rel ⁡ R → R ↾ dom ⁡ R = R
2 1 dmqseqd ⊢ Rel ⁡ R → dom ⁡ R ↾ dom ⁡ R / R ↾ dom ⁡ R = dom ⁡ R / R
3 2 eleq2d ⊢ Rel ⁡ R → A ∈ dom ⁡ R ↾ dom ⁡ R / R ↾ dom ⁡ R ↔ A ∈ dom ⁡ R / R
4 3 adantl ⊢ A ∈ V ∧ Rel ⁡ R → A ∈ dom ⁡ R ↾ dom ⁡ R / R ↾ dom ⁡ R ↔ A ∈ dom ⁡ R / R
5 eldmqsres2 ⊢ A ∈ V → A ∈ dom ⁡ R ↾ dom ⁡ R / R ↾ dom ⁡ R ↔ ∃ u ∈ dom ⁡ R ∃ x ∈ u R A = u R
6 5 adantr ⊢ A ∈ V ∧ Rel ⁡ R → A ∈ dom ⁡ R ↾ dom ⁡ R / R ↾ dom ⁡ R ↔ ∃ u ∈ dom ⁡ R ∃ x ∈ u R A = u R
7 4 6 bitr3d ⊢ A ∈ V ∧ Rel ⁡ R → A ∈ dom ⁡ R / R ↔ ∃ u ∈ dom ⁡ R ∃ x ∈ u R A = u R
8 7 ex ⊢ A ∈ V → Rel ⁡ R → A ∈ dom ⁡ R / R ↔ ∃ u ∈ dom ⁡ R ∃ x ∈ u R A = u R