Metamath Proof Explorer


Theorem relexpcnvd

Description: Commutation of converse and relation exponentiation. (Contributed by Drahflow, 12-Nov-2015) (Revised by RP, 30-May-2020) (Revised by AV, 12-Jul-2024)

Ref Expression
Hypotheses relexpcnvd.1 ⊢ φ → R ∈ V
relexpcnvd.2 ⊢ φ → N ∈ ℕ 0
Assertion relexpcnvd ⊢ φ → R ↑ r N -1 = R -1 ↑ r N

Proof

Step Hyp Ref Expression
1 relexpcnvd.1 ⊢ φ → R ∈ V
2 relexpcnvd.2 ⊢ φ → N ∈ ℕ 0
3 relexpcnv ⊢ N ∈ ℕ 0 ∧ R ∈ V → R ↑ r N -1 = R -1 ↑ r N
4 2 1 3 syl2anc ⊢ φ → R ↑ r N -1 = R -1 ↑ r N