Metamath Proof Explorer


Theorem resiexg

Description: The existence of a restricted identity function, proved without using the Axiom of Replacement (unlike resfunexg ). (Contributed by NM, 13-Jan-2007) (Proof shortened by Peter Mazsa, 2-Oct-2022)

Ref Expression
Assertion resiexg ⊢ A ∈ V → I ↾ A ∈ V

Proof

Step Hyp Ref Expression
1 idssxp ⊢ I ↾ A ⊆ A × A
2 sqxpexg ⊢ A ∈ V → A × A ∈ V
3 ssexg ⊢ I ↾ A ⊆ A × A ∧ A × A ∈ V → I ↾ A ∈ V
4 1 2 3 sylancr ⊢ A ∈ V → I ↾ A ∈ V