Metamath Proof Explorer


Theorem ringassd

Description: Associative law for multiplication in a ring. (Contributed by SN, 14-Aug-2024)

Ref Expression
Hypotheses ringassd.b ⊢ B = Base R
ringassd.t ⊢ · ˙ = ⋅ R
ringassd.r ⊢ φ → R ∈ Ring
ringassd.x ⊢ φ → X ∈ B
ringassd.y ⊢ φ → Y ∈ B
ringassd.z ⊢ φ → Z ∈ B
Assertion ringassd ⊢ φ → X · ˙ Y · ˙ Z = X · ˙ Y · ˙ Z

Proof

Step Hyp Ref Expression
1 ringassd.b ⊢ B = Base R
2 ringassd.t ⊢ · ˙ = ⋅ R
3 ringassd.r ⊢ φ → R ∈ Ring
4 ringassd.x ⊢ φ → X ∈ B
5 ringassd.y ⊢ φ → Y ∈ B
6 ringassd.z ⊢ φ → Z ∈ B
7 1 2 ringass ⊢ R ∈ Ring ∧ X ∈ B ∧ Y ∈ B ∧ Z ∈ B → X · ˙ Y · ˙ Z = X · ˙ Y · ˙ Z
8 3 4 5 6 7 syl13anc ⊢ φ → X · ˙ Y · ˙ Z = X · ˙ Y · ˙ Z