Metamath Proof Explorer


Theorem scottn0f

Description: A version of scott0f with inequalities instead of equalities. (Contributed by Giovanni Mascellani, 19-Aug-2018)

Ref Expression
Hypotheses scottn0f.1 ⊢ Ⅎ _ y A
scottn0f.2 ⊢ Ⅎ _ x A
Assertion scottn0f ⊢ A ≠ ∅ ↔ x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y ≠ ∅

Proof

Step Hyp Ref Expression
1 scottn0f.1 ⊢ Ⅎ _ y A
2 scottn0f.2 ⊢ Ⅎ _ x A
3 1 2 scott0f ⊢ A = ∅ ↔ x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y = ∅
4 3 necon3bii ⊢ A ≠ ∅ ↔ x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y ≠ ∅