Metamath Proof Explorer


Theorem simprbda

Description: Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007)

Ref Expression
Hypothesis simplbda.1 ⊢ φ → ψ ↔ χ ∧ θ
Assertion simprbda ⊢ φ ∧ ψ → χ

Proof

Step Hyp Ref Expression
1 simplbda.1 ⊢ φ → ψ ↔ χ ∧ θ
2 1 biimpa ⊢ φ ∧ ψ → χ ∧ θ
3 2 simpld ⊢ φ ∧ ψ → χ