Metamath Proof Explorer


Theorem ssequn2

Description: A relationship between subclass and union. (Contributed by NM, 13-Jun-1994)

Ref Expression
Assertion ssequn2 ⊢ A ⊆ B ↔ B ∪ A = B

Proof

Step Hyp Ref Expression
1 ssequn1 ⊢ A ⊆ B ↔ A ∪ B = B
2 uncom ⊢ A ∪ B = B ∪ A
3 2 eqeq1i ⊢ A ∪ B = B ↔ B ∪ A = B
4 1 3 bitri ⊢ A ⊆ B ↔ B ∪ A = B