Metamath Proof Explorer


Theorem subsubs2d

Description: Law for double surreal subtraction. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Hypotheses subsubs4d.1 ⊢ φ → A ∈ No
subsubs4d.2 ⊢ φ → B ∈ No
subsubs4d.3 ⊢ φ → C ∈ No
Assertion subsubs2d ⊢ φ → A - s B - s C = A + s C - s B

Proof

Step Hyp Ref Expression
1 subsubs4d.1 ⊢ φ → A ∈ No
2 subsubs4d.2 ⊢ φ → B ∈ No
3 subsubs4d.3 ⊢ φ → C ∈ No
4 2 3 subscld ⊢ φ → B - s C ∈ No
5 1 4 subsvald ⊢ φ → A - s B - s C = A + s + s ⁡ B - s C
6 2 3 negsubsdi2d ⊢ φ → + s ⁡ B - s C = C - s B
7 6 oveq2d ⊢ φ → A + s + s ⁡ B - s C = A + s C - s B
8 5 7 eqtrd ⊢ φ → A - s B - s C = A + s C - s B