Metamath Proof Explorer


Theorem sumeq12sdv

Description: Equality deduction for sum. General version of sumeq2sdv . (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypotheses sumeq12sdv.1 ⊢ φ → A = B
sumeq12sdv.2 ⊢ φ → C = D
Assertion sumeq12sdv ⊢ φ → ∑ k ∈ A C = ∑ k ∈ B D

Proof

Step Hyp Ref Expression
1 sumeq12sdv.1 ⊢ φ → A = B
2 sumeq12sdv.2 ⊢ φ → C = D
3 1 sumeq1d ⊢ φ → ∑ k ∈ A C = ∑ k ∈ B C
4 2 sumeq2sdv ⊢ φ → ∑ k ∈ B C = ∑ k ∈ B D
5 3 4 eqtrd ⊢ φ → ∑ k ∈ A C = ∑ k ∈ B D