Metamath Proof Explorer


Theorem symg1bas

Description: The symmetric group on a singleton is the symmetric group S_1 consisting of the identity only. (Contributed by AV, 9-Dec-2018)

Ref Expression
Hypotheses symg1bas.1 ⊢ G = SymGrp ⁡ A
symg1bas.2 ⊢ B = Base G
symg1bas.0 ⊢ A = I
Assertion symg1bas ⊢ I ∈ V → B = I I

Proof

Step Hyp Ref Expression
1 symg1bas.1 ⊢ G = SymGrp ⁡ A
2 symg1bas.2 ⊢ B = Base G
3 symg1bas.0 ⊢ A = I
4 1 2 symgbas ⊢ B = f | f : A ⟶ 1-1 onto A
5 eqidd ⊢ A = I → p = p
6 id ⊢ A = I → A = I
7 5 6 6 f1oeq123d ⊢ A = I → p : A ⟶ 1-1 onto A ↔ p : I ⟶ 1-1 onto I
8 3 7 ax-mp ⊢ p : A ⟶ 1-1 onto A ↔ p : I ⟶ 1-1 onto I
9 f1of ⊢ p : I ⟶ 1-1 onto I → p : I ⟶ I
10 fsng ⊢ I ∈ V ∧ I ∈ V → p : I ⟶ I ↔ p = I I
11 10 anidms ⊢ I ∈ V → p : I ⟶ I ↔ p = I I
12 9 11 imbitrid ⊢ I ∈ V → p : I ⟶ 1-1 onto I → p = I I
13 f1osng ⊢ I ∈ V ∧ I ∈ V → I I : I ⟶ 1-1 onto I
14 13 anidms ⊢ I ∈ V → I I : I ⟶ 1-1 onto I
15 f1oeq1 ⊢ p = I I → p : I ⟶ 1-1 onto I ↔ I I : I ⟶ 1-1 onto I
16 14 15 syl5ibrcom ⊢ I ∈ V → p = I I → p : I ⟶ 1-1 onto I
17 12 16 impbid ⊢ I ∈ V → p : I ⟶ 1-1 onto I ↔ p = I I
18 8 17 bitrid ⊢ I ∈ V → p : A ⟶ 1-1 onto A ↔ p = I I
19 vex ⊢ p ∈ V
20 f1oeq1 ⊢ f = p → f : A ⟶ 1-1 onto A ↔ p : A ⟶ 1-1 onto A
21 19 20 elab ⊢ p ∈ f | f : A ⟶ 1-1 onto A ↔ p : A ⟶ 1-1 onto A
22 velsn ⊢ p ∈ I I ↔ p = I I
23 18 21 22 3bitr4g ⊢ I ∈ V → p ∈ f | f : A ⟶ 1-1 onto A ↔ p ∈ I I
24 23 eqrdv ⊢ I ∈ V → f | f : A ⟶ 1-1 onto A = I I
25 4 24 eqtrid ⊢ I ∈ V → B = I I