Metamath Proof Explorer


Theorem tgaasncol

Description: Slide a non-collinearity along the line it is off: if X is off line Y Z and W is a point of that line other than Z , then X is off line Z W too. Lines Z Y and Z W coincide ( tglineeltr ), which is what the exterior-angle hypothesis of tgaasexc needs at the moving point. (Contributed by JAG, 12-Aug-2026)

Ref Expression
Hypotheses tgaasncol.p ⊢ P = Base G
tgaasncol.i ⊢ I = Itv ⁡ G
tgaasncol.l ⊢ L = Line 𝒢 ⁡ G
tgaasncol.g ⊢ φ → G ∈ 𝒢 Tarski
tgaasncol.x ⊢ φ → X ∈ P
tgaasncol.y ⊢ φ → Y ∈ P
tgaasncol.z ⊢ φ → Z ∈ P
tgaasncol.w ⊢ φ → W ∈ P
tgaasncol.1 ⊢ φ → ¬ X ∈ Y L Z ∨ Y = Z
tgaasncol.2 ⊢ φ → W ∈ Z L Y ∨ Z = Y
tgaasncol.3 ⊢ φ → W ≠ Z
Assertion tgaasncol ⊢ φ → ¬ X ∈ Z L W ∨ Z = W

Proof

Step Hyp Ref Expression
1 tgaasncol.p ⊢ P = Base G
2 tgaasncol.i ⊢ I = Itv ⁡ G
3 tgaasncol.l ⊢ L = Line 𝒢 ⁡ G
4 tgaasncol.g ⊢ φ → G ∈ 𝒢 Tarski
5 tgaasncol.x ⊢ φ → X ∈ P
6 tgaasncol.y ⊢ φ → Y ∈ P
7 tgaasncol.z ⊢ φ → Z ∈ P
8 tgaasncol.w ⊢ φ → W ∈ P
9 tgaasncol.1 ⊢ φ → ¬ X ∈ Y L Z ∨ Y = Z
10 tgaasncol.2 ⊢ φ → W ∈ Z L Y ∨ Z = Y
11 tgaasncol.3 ⊢ φ → W ≠ Z
12 1 3 2 4 6 7 5 9 ncolcom ⊢ φ → ¬ X ∈ Z L Y ∨ Z = Y
13 4 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → G ∈ 𝒢 Tarski
14 7 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → Z ∈ P
15 6 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → Y ∈ P
16 1 3 2 4 6 7 5 9 ncolrot1 ⊢ φ → ¬ Y ∈ Z L X ∨ Z = X
17 1 2 3 4 6 7 5 16 ncolne1 ⊢ φ → Y ≠ Z
18 17 necomd ⊢ φ → Z ≠ Y
19 18 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → Z ≠ Y
20 8 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → W ∈ P
21 11 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → W ≠ Z
22 18 neneqd ⊢ φ → ¬ Z = Y
23 10 22 olcnd ⊢ φ → W ∈ Z L Y
24 23 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → W ∈ Z L Y
25 5 adantr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → X ∈ P
26 simpr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → X ∈ Z L W ∨ Z = W
27 21 necomd ⊢ φ ∧ X ∈ Z L W ∨ Z = W → Z ≠ W
28 27 neneqd ⊢ φ ∧ X ∈ Z L W ∨ Z = W → ¬ Z = W
29 26 28 olcnd ⊢ φ ∧ X ∈ Z L W ∨ Z = W → X ∈ Z L W
30 1 2 3 13 14 15 19 20 21 24 25 29 tglineeltr ⊢ φ ∧ X ∈ Z L W ∨ Z = W → X ∈ Z L Y
31 30 orcd ⊢ φ ∧ X ∈ Z L W ∨ Z = W → X ∈ Z L Y ∨ Z = Y
32 12 31 mtand ⊢ φ → ¬ X ∈ Z L W ∨ Z = W