Metamath Proof Explorer


Theorem threehalves

Description: Example theorem demonstrating decimal expansions. (Contributed by Thierry Arnoux, 27-Dec-2021)

Ref Expression
Assertion threehalves ⊢ 3 2 = 1.5

Proof

Step Hyp Ref Expression
1 3re ⊢ 3 ∈ ℝ
2 2re ⊢ 2 ∈ ℝ
3 2ne0 ⊢ 2 ≠ 0
4 1 2 3 redivcli ⊢ 3 2 ∈ ℝ
5 4 recni ⊢ 3 2 ∈ ℂ
6 1nn0 ⊢ 1 ∈ ℕ 0
7 5re ⊢ 5 ∈ ℝ
8 dpcl ⊢ 1 ∈ ℕ 0 ∧ 5 ∈ ℝ → 1.5 ∈ ℝ
9 6 7 8 mp2an ⊢ 1.5 ∈ ℝ
10 9 recni ⊢ 1.5 ∈ ℂ
11 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
12 5 10 11 3pm3.2i ⊢ 3 2 ∈ ℂ ∧ 1.5 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0
13 5nn0 ⊢ 5 ∈ ℕ 0
14 3nn0 ⊢ 3 ∈ ℕ 0
15 0nn0 ⊢ 0 ∈ ℕ 0
16 eqid ⊢ 15 = 15
17 df-2 ⊢ 2 = 1 + 1
18 17 oveq1i ⊢ 2 + 1 = 1 + 1 + 1
19 2p1e3 ⊢ 2 + 1 = 3
20 18 19 eqtr3i ⊢ 1 + 1 + 1 = 3
21 5p5e10 ⊢ 5 + 5 = 10
22 6 13 6 13 16 16 20 15 21 decaddc ⊢ 15 + 15 = 30
23 6 13 6 13 14 15 22 dpadd ⊢ 1.5 + 1.5 = 3.0
24 14 dp0u ⊢ 3.0 = 3
25 23 24 eqtri ⊢ 1.5 + 1.5 = 3
26 10 times2i ⊢ 1.5 ⋅ 2 = 1.5 + 1.5
27 1 recni ⊢ 3 ∈ ℂ
28 11 simpli ⊢ 2 ∈ ℂ
29 27 28 3 divcan1i ⊢ 3 2 ⋅ 2 = 3
30 25 26 29 3eqtr4ri ⊢ 3 2 ⋅ 2 = 1.5 ⋅ 2
31 mulcan2 ⊢ 3 2 ∈ ℂ ∧ 1.5 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 3 2 ⋅ 2 = 1.5 ⋅ 2 ↔ 3 2 = 1.5
32 31 biimpa ⊢ 3 2 ∈ ℂ ∧ 1.5 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 3 2 ⋅ 2 = 1.5 ⋅ 2 → 3 2 = 1.5
33 12 30 32 mp2an ⊢ 3 2 = 1.5