Metamath Proof Explorer
Description: The only subgroup of a trivial group is itself. (Contributed by Rohan
Ridenour, 3-Aug-2023)
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Ref |
Expression |
|
Hypotheses |
trivsubgd.1 |
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|
trivsubgd.2 |
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trivsubgd.3 |
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trivsubgd.4 |
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trivsubgd.5 |
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|
Assertion |
trivsubgd |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
trivsubgd.1 |
|
| 2 |
|
trivsubgd.2 |
|
| 3 |
|
trivsubgd.3 |
|
| 4 |
|
trivsubgd.4 |
|
| 5 |
|
trivsubgd.5 |
|
| 6 |
1
|
subgss |
|
| 7 |
5 6
|
syl |
|
| 8 |
7 4
|
sseqtrd |
|
| 9 |
2
|
subg0cl |
|
| 10 |
5 9
|
syl |
|
| 11 |
10
|
snssd |
|
| 12 |
8 11
|
eqssd |
|
| 13 |
12 4
|
eqtr4d |
|