Metamath Proof Explorer
Description: The only subgroup of a trivial group is itself. (Contributed by Rohan
Ridenour, 3-Aug-2023)
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Ref |
Expression |
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Hypotheses |
trivsubgd.1 |
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trivsubgd.2 |
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trivsubgd.3 |
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trivsubgd.4 |
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trivsubgd.5 |
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Assertion |
trivsubgd |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
trivsubgd.1 |
|
2 |
|
trivsubgd.2 |
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3 |
|
trivsubgd.3 |
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4 |
|
trivsubgd.4 |
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5 |
|
trivsubgd.5 |
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6 |
1
|
subgss |
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7 |
5 6
|
syl |
|
8 |
7 4
|
sseqtrd |
|
9 |
2
|
subg0cl |
|
10 |
5 9
|
syl |
|
11 |
10
|
snssd |
|
12 |
8 11
|
eqssd |
|
13 |
12 4
|
eqtr4d |
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