Metamath Proof Explorer


Theorem trivsubgsnd

Description: The only subgroup of a trivial group is itself. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses trivsubgsnd.1 ⊢ B = Base G
trivsubgsnd.2 ⊢ 0 ˙ = 0 G
trivsubgsnd.3 ⊢ φ → G ∈ Grp
trivsubgsnd.4 ⊢ φ → B = 0 ˙
Assertion trivsubgsnd ⊢ φ → SubGrp ⁡ G = B

Proof

Step Hyp Ref Expression
1 trivsubgsnd.1 ⊢ B = Base G
2 trivsubgsnd.2 ⊢ 0 ˙ = 0 G
3 trivsubgsnd.3 ⊢ φ → G ∈ Grp
4 trivsubgsnd.4 ⊢ φ → B = 0 ˙
5 3 adantr ⊢ φ ∧ x ∈ SubGrp ⁡ G → G ∈ Grp
6 4 adantr ⊢ φ ∧ x ∈ SubGrp ⁡ G → B = 0 ˙
7 simpr ⊢ φ ∧ x ∈ SubGrp ⁡ G → x ∈ SubGrp ⁡ G
8 1 2 5 6 7 trivsubgd ⊢ φ ∧ x ∈ SubGrp ⁡ G → x = B
9 velsn ⊢ x ∈ B ↔ x = B
10 8 9 sylibr ⊢ φ ∧ x ∈ SubGrp ⁡ G → x ∈ B
11 10 ex ⊢ φ → x ∈ SubGrp ⁡ G → x ∈ B
12 11 ssrdv ⊢ φ → SubGrp ⁡ G ⊆ B
13 1 subgid ⊢ G ∈ Grp → B ∈ SubGrp ⁡ G
14 3 13 syl ⊢ φ → B ∈ SubGrp ⁡ G
15 14 snssd ⊢ φ → B ⊆ SubGrp ⁡ G
16 12 15 eqssd ⊢ φ → SubGrp ⁡ G = B