Metamath Proof Explorer
		
		
		
		Description:  The only subgroup of a trivial group is itself.  (Contributed by Rohan
       Ridenour, 3-Aug-2023)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | trivsubgd.1 |  | 
					
						|  |  | trivsubgd.2 |  | 
					
						|  |  | trivsubgd.3 |  | 
					
						|  |  | trivsubgd.4 |  | 
					
						|  |  | trivsubgd.5 |  | 
				
					|  | Assertion | trivsubgd |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | trivsubgd.1 |  | 
						
							| 2 |  | trivsubgd.2 |  | 
						
							| 3 |  | trivsubgd.3 |  | 
						
							| 4 |  | trivsubgd.4 |  | 
						
							| 5 |  | trivsubgd.5 |  | 
						
							| 6 | 1 | subgss |  | 
						
							| 7 | 5 6 | syl |  | 
						
							| 8 | 7 4 | sseqtrd |  | 
						
							| 9 | 2 | subg0cl |  | 
						
							| 10 | 5 9 | syl |  | 
						
							| 11 | 10 | snssd |  | 
						
							| 12 | 8 11 | eqssd |  | 
						
							| 13 | 12 4 | eqtr4d |  |