Metamath Proof Explorer


Theorem tsna1

Description: A Tseitin axiom for logical incompatibility, in deduction form. (Contributed by Giovanni Mascellani, 24-Mar-2018)

Ref Expression
Assertion tsna1 ⊢ θ → ¬ φ ∨ ¬ ψ ∨ ¬ φ ⊼ ψ

Proof

Step Hyp Ref Expression
1 tsan1 ⊢ θ → ¬ φ ∨ ¬ ψ ∨ φ ∧ ψ
2 notnotb ⊢ φ ⊼ ψ ↔ ¬ ¬ φ ⊼ ψ
3 df-nan ⊢ φ ⊼ ψ ↔ ¬ φ ∧ ψ
4 2 3 bitr3i ⊢ ¬ ¬ φ ⊼ ψ ↔ ¬ φ ∧ ψ
5 4 con4bii ⊢ ¬ φ ⊼ ψ ↔ φ ∧ ψ
6 5 orbi2i ⊢ ¬ φ ∨ ¬ ψ ∨ ¬ φ ⊼ ψ ↔ ¬ φ ∨ ¬ ψ ∨ φ ∧ ψ
7 1 6 sylibr ⊢ θ → ¬ φ ∨ ¬ ψ ∨ ¬ φ ⊼ ψ