Metamath Proof Explorer


Theorem xkobval

Description: Alternative expression for the subbase of the compact-open topology. (Contributed by Mario Carneiro, 23-Mar-2015)

Ref Expression
Hypotheses xkoval.x ⊢ X = ⋃ R
xkoval.k ⊢ K = x ∈ 𝒫 X | R ↾ 𝑡 x ∈ Comp
xkoval.t ⊢ T = k ∈ K , v ∈ S ⟼ f ∈ R Cn S | f k ⊆ v
Assertion xkobval ⊢ ran ⁡ T = s | ∃ k ∈ 𝒫 X ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v

Proof

Step Hyp Ref Expression
1 xkoval.x ⊢ X = ⋃ R
2 xkoval.k ⊢ K = x ∈ 𝒫 X | R ↾ 𝑡 x ∈ Comp
3 xkoval.t ⊢ T = k ∈ K , v ∈ S ⟼ f ∈ R Cn S | f k ⊆ v
4 3 rnmpo ⊢ ran ⁡ T = s | ∃ k ∈ K ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v
5 oveq2 ⊢ x = k → R ↾ 𝑡 x = R ↾ 𝑡 k
6 5 eleq1d ⊢ x = k → R ↾ 𝑡 x ∈ Comp ↔ R ↾ 𝑡 k ∈ Comp
7 6 rexrab ⊢ ∃ k ∈ x ∈ 𝒫 X | R ↾ 𝑡 x ∈ Comp ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v ↔ ∃ k ∈ 𝒫 X R ↾ 𝑡 k ∈ Comp ∧ ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v
8 2 rexeqi ⊢ ∃ k ∈ K ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v ↔ ∃ k ∈ x ∈ 𝒫 X | R ↾ 𝑡 x ∈ Comp ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v
9 r19.42v ⊢ ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v ↔ R ↾ 𝑡 k ∈ Comp ∧ ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v
10 9 rexbii ⊢ ∃ k ∈ 𝒫 X ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v ↔ ∃ k ∈ 𝒫 X R ↾ 𝑡 k ∈ Comp ∧ ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v
11 7 8 10 3bitr4i ⊢ ∃ k ∈ K ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v ↔ ∃ k ∈ 𝒫 X ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v
12 11 abbii ⊢ s | ∃ k ∈ K ∃ v ∈ S s = f ∈ R Cn S | f k ⊆ v = s | ∃ k ∈ 𝒫 X ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v
13 4 12 eqtri ⊢ ran ⁡ T = s | ∃ k ∈ 𝒫 X ∃ v ∈ S R ↾ 𝑡 k ∈ Comp ∧ s = f ∈ R Cn S | f k ⊆ v