Metamath Proof Explorer


Theorem xpdom3

Description: A set is dominated by its Cartesian product with a nonempty set. Exercise 6 of Suppes p. 98. (Contributed by NM, 27-Jul-2004) (Revised by Mario Carneiro, 29-Apr-2015)

Ref Expression
Assertion xpdom3 ⊢ A ∈ V ∧ B ∈ W ∧ B ≠ ∅ → A ≼ A × B

Proof

Step Hyp Ref Expression
1 n0 ⊢ B ≠ ∅ ↔ ∃ x x ∈ B
2 xpsneng ⊢ A ∈ V ∧ x ∈ B → A × x ≈ A
3 2 3adant2 ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A × x ≈ A
4 3 ensymd ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A ≈ A × x
5 xpexg ⊢ A ∈ V ∧ B ∈ W → A × B ∈ V
6 5 3adant3 ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A × B ∈ V
7 simp3 ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → x ∈ B
8 7 snssd ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → x ⊆ B
9 xpss2 ⊢ x ⊆ B → A × x ⊆ A × B
10 8 9 syl ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A × x ⊆ A × B
11 ssdomg ⊢ A × B ∈ V → A × x ⊆ A × B → A × x ≼ A × B
12 6 10 11 sylc ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A × x ≼ A × B
13 endomtr ⊢ A ≈ A × x ∧ A × x ≼ A × B → A ≼ A × B
14 4 12 13 syl2anc ⊢ A ∈ V ∧ B ∈ W ∧ x ∈ B → A ≼ A × B
15 14 3expia ⊢ A ∈ V ∧ B ∈ W → x ∈ B → A ≼ A × B
16 15 exlimdv ⊢ A ∈ V ∧ B ∈ W → ∃ x x ∈ B → A ≼ A × B
17 1 16 biimtrid ⊢ A ∈ V ∧ B ∈ W → B ≠ ∅ → A ≼ A × B
18 17 3impia ⊢ A ∈ V ∧ B ∈ W ∧ B ≠ ∅ → A ≼ A × B