Metamath Proof Explorer


Theorem xpima

Description: Direct image by a Cartesian product. (Contributed by Thierry Arnoux, 4-Feb-2017)

Ref Expression
Assertion xpima ⊢ A × B C = if A ∩ C = ∅ ∅ B

Proof

Step Hyp Ref Expression
1 exmid ⊢ A ∩ C = ∅ ∨ ¬ A ∩ C = ∅
2 df-ima ⊢ A × B C = ran ⁡ A × B ↾ C
3 df-res ⊢ A × B ↾ C = A × B ∩ C × V
4 3 rneqi ⊢ ran ⁡ A × B ↾ C = ran ⁡ A × B ∩ C × V
5 2 4 eqtri ⊢ A × B C = ran ⁡ A × B ∩ C × V
6 inxp ⊢ A × B ∩ C × V = A ∩ C × B ∩ V
7 6 rneqi ⊢ ran ⁡ A × B ∩ C × V = ran ⁡ A ∩ C × B ∩ V
8 inv1 ⊢ B ∩ V = B
9 8 xpeq2i ⊢ A ∩ C × B ∩ V = A ∩ C × B
10 9 rneqi ⊢ ran ⁡ A ∩ C × B ∩ V = ran ⁡ A ∩ C × B
11 5 7 10 3eqtri ⊢ A × B C = ran ⁡ A ∩ C × B
12 xpeq1 ⊢ A ∩ C = ∅ → A ∩ C × B = ∅ × B
13 0xp ⊢ ∅ × B = ∅
14 12 13 eqtrdi ⊢ A ∩ C = ∅ → A ∩ C × B = ∅
15 14 rneqd ⊢ A ∩ C = ∅ → ran ⁡ A ∩ C × B = ran ⁡ ∅
16 rn0 ⊢ ran ⁡ ∅ = ∅
17 15 16 eqtrdi ⊢ A ∩ C = ∅ → ran ⁡ A ∩ C × B = ∅
18 11 17 eqtrid ⊢ A ∩ C = ∅ → A × B C = ∅
19 18 ancli ⊢ A ∩ C = ∅ → A ∩ C = ∅ ∧ A × B C = ∅
20 df-ne ⊢ A ∩ C ≠ ∅ ↔ ¬ A ∩ C = ∅
21 rnxp ⊢ A ∩ C ≠ ∅ → ran ⁡ A ∩ C × B = B
22 20 21 sylbir ⊢ ¬ A ∩ C = ∅ → ran ⁡ A ∩ C × B = B
23 11 22 eqtrid ⊢ ¬ A ∩ C = ∅ → A × B C = B
24 23 ancli ⊢ ¬ A ∩ C = ∅ → ¬ A ∩ C = ∅ ∧ A × B C = B
25 19 24 orim12i ⊢ A ∩ C = ∅ ∨ ¬ A ∩ C = ∅ → A ∩ C = ∅ ∧ A × B C = ∅ ∨ ¬ A ∩ C = ∅ ∧ A × B C = B
26 1 25 ax-mp ⊢ A ∩ C = ∅ ∧ A × B C = ∅ ∨ ¬ A ∩ C = ∅ ∧ A × B C = B
27 eqif ⊢ A × B C = if A ∩ C = ∅ ∅ B ↔ A ∩ C = ∅ ∧ A × B C = ∅ ∨ ¬ A ∩ C = ∅ ∧ A × B C = B
28 26 27 mpbir ⊢ A × B C = if A ∩ C = ∅ ∅ B