Metamath Proof Explorer


Theorem zlmodzxzequa

Description: Example of an equation within the ZZ-module ZZ X. ZZ (see example in Roman p. 112 for a linearly dependent set). (Contributed by AV, 22-May-2019) (Revised by AV, 10-Jun-2019)

Ref Expression
Hypotheses zlmodzxzequa.z ⊢ Z = ℤ ring freeLMod 0 1
zlmodzxzequa.o ⊢ 0 ˙ = 0 0 1 0
zlmodzxzequa.t ⊢ ∙ ˙ = ⋅ Z
zlmodzxzequa.m ⊢ - ˙ = - Z
zlmodzxzequa.a ⊢ A = 0 3 1 6
zlmodzxzequa.b ⊢ B = 0 2 1 4
Assertion zlmodzxzequa ⊢ 2 ∙ ˙ A - ˙ 3 ∙ ˙ B = 0 ˙

Proof

Step Hyp Ref Expression
1 zlmodzxzequa.z ⊢ Z = ℤ ring freeLMod 0 1
2 zlmodzxzequa.o ⊢ 0 ˙ = 0 0 1 0
3 zlmodzxzequa.t ⊢ ∙ ˙ = ⋅ Z
4 zlmodzxzequa.m ⊢ - ˙ = - Z
5 zlmodzxzequa.a ⊢ A = 0 3 1 6
6 zlmodzxzequa.b ⊢ B = 0 2 1 4
7 3cn ⊢ 3 ∈ ℂ
8 7 2timesi ⊢ 2 ⋅ 3 = 3 + 3
9 3p3e6 ⊢ 3 + 3 = 6
10 8 9 eqtri ⊢ 2 ⋅ 3 = 6
11 3t2e6 ⊢ 3 ⋅ 2 = 6
12 10 11 oveq12i ⊢ 2 ⋅ 3 − 3 ⋅ 2 = 6 − 6
13 6cn ⊢ 6 ∈ ℂ
14 13 subidi ⊢ 6 − 6 = 0
15 12 14 eqtri ⊢ 2 ⋅ 3 − 3 ⋅ 2 = 0
16 15 opeq2i ⊢ 0 2 ⋅ 3 − 3 ⋅ 2 = 0 0
17 2t6m3t4e0 ⊢ 2 ⋅ 6 − 3 ⋅ 4 = 0
18 17 opeq2i ⊢ 1 2 ⋅ 6 − 3 ⋅ 4 = 1 0
19 16 18 preq12i ⊢ 0 2 ⋅ 3 − 3 ⋅ 2 1 2 ⋅ 6 − 3 ⋅ 4 = 0 0 1 0
20 5 oveq2i ⊢ 2 ∙ ˙ A = 2 ∙ ˙ 0 3 1 6
21 2z ⊢ 2 ∈ ℤ
22 3z ⊢ 3 ∈ ℤ
23 6nn ⊢ 6 ∈ ℕ
24 23 nnzi ⊢ 6 ∈ ℤ
25 1 3 zlmodzxzscm ⊢ 2 ∈ ℤ ∧ 3 ∈ ℤ ∧ 6 ∈ ℤ → 2 ∙ ˙ 0 3 1 6 = 0 2 ⋅ 3 1 2 ⋅ 6
26 21 22 24 25 mp3an ⊢ 2 ∙ ˙ 0 3 1 6 = 0 2 ⋅ 3 1 2 ⋅ 6
27 20 26 eqtri ⊢ 2 ∙ ˙ A = 0 2 ⋅ 3 1 2 ⋅ 6
28 6 oveq2i ⊢ 3 ∙ ˙ B = 3 ∙ ˙ 0 2 1 4
29 4z ⊢ 4 ∈ ℤ
30 1 3 zlmodzxzscm ⊢ 3 ∈ ℤ ∧ 2 ∈ ℤ ∧ 4 ∈ ℤ → 3 ∙ ˙ 0 2 1 4 = 0 3 ⋅ 2 1 3 ⋅ 4
31 22 21 29 30 mp3an ⊢ 3 ∙ ˙ 0 2 1 4 = 0 3 ⋅ 2 1 3 ⋅ 4
32 28 31 eqtri ⊢ 3 ∙ ˙ B = 0 3 ⋅ 2 1 3 ⋅ 4
33 27 32 oveq12i ⊢ 2 ∙ ˙ A - ˙ 3 ∙ ˙ B = 0 2 ⋅ 3 1 2 ⋅ 6 - ˙ 0 3 ⋅ 2 1 3 ⋅ 4
34 zmulcl ⊢ 2 ∈ ℤ ∧ 3 ∈ ℤ → 2 ⋅ 3 ∈ ℤ
35 21 22 34 mp2an ⊢ 2 ⋅ 3 ∈ ℤ
36 zmulcl ⊢ 3 ∈ ℤ ∧ 2 ∈ ℤ → 3 ⋅ 2 ∈ ℤ
37 22 21 36 mp2an ⊢ 3 ⋅ 2 ∈ ℤ
38 zmulcl ⊢ 2 ∈ ℤ ∧ 6 ∈ ℤ → 2 ⋅ 6 ∈ ℤ
39 21 24 38 mp2an ⊢ 2 ⋅ 6 ∈ ℤ
40 zmulcl ⊢ 3 ∈ ℤ ∧ 4 ∈ ℤ → 3 ⋅ 4 ∈ ℤ
41 22 29 40 mp2an ⊢ 3 ⋅ 4 ∈ ℤ
42 1 4 zlmodzxzsub ⊢ 2 ⋅ 3 ∈ ℤ ∧ 3 ⋅ 2 ∈ ℤ ∧ 2 ⋅ 6 ∈ ℤ ∧ 3 ⋅ 4 ∈ ℤ → 0 2 ⋅ 3 1 2 ⋅ 6 - ˙ 0 3 ⋅ 2 1 3 ⋅ 4 = 0 2 ⋅ 3 − 3 ⋅ 2 1 2 ⋅ 6 − 3 ⋅ 4
43 35 37 39 41 42 mp4an ⊢ 0 2 ⋅ 3 1 2 ⋅ 6 - ˙ 0 3 ⋅ 2 1 3 ⋅ 4 = 0 2 ⋅ 3 − 3 ⋅ 2 1 2 ⋅ 6 − 3 ⋅ 4
44 33 43 eqtri ⊢ 2 ∙ ˙ A - ˙ 3 ∙ ˙ B = 0 2 ⋅ 3 − 3 ⋅ 2 1 2 ⋅ 6 − 3 ⋅ 4
45 19 44 2 3eqtr4i ⊢ 2 ∙ ˙ A - ˙ 3 ∙ ˙ B = 0 ˙