Metamath Proof Explorer


Theorem 0fsupp

Description: The empty set is a finitely supported function. (Contributed by AV, 19-Jul-2019)

Ref Expression
Assertion 0fsupp ( 𝑍 ∈ 𝑉 → ∅ finSupp 𝑍 )

Proof

Step Hyp Ref Expression
1 supp0 ⊢ ( 𝑍 ∈ 𝑉 → ( ∅ supp 𝑍 ) = ∅ )
2 0fi ⊢ ∅ ∈ Fin
3 1 2 eqeltrdi ⊢ ( 𝑍 ∈ 𝑉 → ( ∅ supp 𝑍 ) ∈ Fin )
4 fun0 ⊢ Fun ∅
5 0ex ⊢ ∅ ∈ V
6 funisfsupp ⊢ ( ( Fun ∅ ∧ ∅ ∈ V ∧ 𝑍 ∈ 𝑉 ) → ( ∅ finSupp 𝑍 ↔ ( ∅ supp 𝑍 ) ∈ Fin ) )
7 4 5 6 mp3an12 ⊢ ( 𝑍 ∈ 𝑉 → ( ∅ finSupp 𝑍 ↔ ( ∅ supp 𝑍 ) ∈ Fin ) )
8 3 7 mpbird ⊢ ( 𝑍 ∈ 𝑉 → ∅ finSupp 𝑍 )