Metamath Proof Explorer


Theorem 1p1e2s

Description: One plus one is two. Surreal version. (Contributed by Scott Fenton, 27-May-2025)

Ref Expression
Assertion 1p1e2s ( 1s +s 1s ) = 2s

Proof

Step Hyp Ref Expression
1 1n0s 1s ∈ ℕ0s
2 n0cut2 ( 1s ∈ ℕ0s → ( 1s +s 1s ) = ( { 1s } |s ∅ ) )
3 1 2 ax-mp ( 1s +s 1s ) = ( { 1s } |s ∅ )
4 df-2s 2s = ( { 1s } |s ∅ )
5 3 4 eqtr4i ( 1s +s 1s ) = 2s