Metamath Proof Explorer


Theorem 2reucom

Description: Double restricted existential uniqueness commutes. (Contributed by Thierry Arnoux, 4-Jul-2023)

Ref Expression
Assertion 2reucom ( ∃! 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 𝜑 ↔ ∃! 𝑦 ∈ 𝐵 , 𝑥 ∈ 𝐴 𝜑 )

Proof

Step Hyp Ref Expression
1 ancom ⊢ ( ( ∃! 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ∧ ∃! 𝑦 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∃! 𝑦 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃! 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ) )
2 df-2reu ⊢ ( ∃! 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 𝜑 ↔ ( ∃! 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ∧ ∃! 𝑦 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 𝜑 ) )
3 df-2reu ⊢ ( ∃! 𝑦 ∈ 𝐵 , 𝑥 ∈ 𝐴 𝜑 ↔ ( ∃! 𝑦 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃! 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ) )
4 1 2 3 3bitr4i ⊢ ( ∃! 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 𝜑 ↔ ∃! 𝑦 ∈ 𝐵 , 𝑥 ∈ 𝐴 𝜑 )