Metamath Proof Explorer


Theorem 2rexsb

Description: An equivalent expression for double restricted existence, analogous to rexsb . (Contributed by Alexander van der Vekens, 1-Jul-2017)

Ref Expression
Assertion 2rexsb ( ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ↔ ∃ 𝑧 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )

Proof

Step Hyp Ref Expression
1 rexsb ⊢ ( ∃ 𝑦 ∈ 𝐵 𝜑 ↔ ∃ 𝑤 ∈ 𝐵 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) )
2 1 rexbii ⊢ ( ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ↔ ∃ 𝑥 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) )
3 rexcom ⊢ ( ∃ 𝑥 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ↔ ∃ 𝑤 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) )
4 2 3 bitri ⊢ ( ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ↔ ∃ 𝑤 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) )
5 rexsb ⊢ ( ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ↔ ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ( 𝑥 = 𝑧 → ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ) )
6 impexp ⊢ ( ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) ↔ ( 𝑥 = 𝑧 → ( 𝑦 = 𝑤 → 𝜑 ) ) )
7 6 albii ⊢ ( ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) ↔ ∀ 𝑦 ( 𝑥 = 𝑧 → ( 𝑦 = 𝑤 → 𝜑 ) ) )
8 19.21v ⊢ ( ∀ 𝑦 ( 𝑥 = 𝑧 → ( 𝑦 = 𝑤 → 𝜑 ) ) ↔ ( 𝑥 = 𝑧 → ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ) )
9 7 8 bitr2i ⊢ ( ( 𝑥 = 𝑧 → ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ) ↔ ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
10 9 albii ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑧 → ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ) ↔ ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
11 10 rexbii ⊢ ( ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ( 𝑥 = 𝑧 → ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ) ↔ ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
12 5 11 bitri ⊢ ( ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ↔ ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
13 12 rexbii ⊢ ( ∃ 𝑤 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ↔ ∃ 𝑤 ∈ 𝐵 ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
14 rexcom ⊢ ( ∃ 𝑤 ∈ 𝐵 ∃ 𝑧 ∈ 𝐴 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) ↔ ∃ 𝑧 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
15 13 14 bitri ⊢ ( ∃ 𝑤 ∈ 𝐵 ∃ 𝑥 ∈ 𝐴 ∀ 𝑦 ( 𝑦 = 𝑤 → 𝜑 ) ↔ ∃ 𝑧 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )
16 4 15 bitri ⊢ ( ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜑 ↔ ∃ 𝑧 ∈ 𝐴 ∃ 𝑤 ∈ 𝐵 ∀ 𝑥 ∀ 𝑦 ( ( 𝑥 = 𝑧 ∧ 𝑦 = 𝑤 ) → 𝜑 ) )